J James Member Aug 7, 2025 #1 I'm trying to figure out how many particles are in 8.1 moles of C₂H₄O. Can someone explain the steps to calculate this?
I'm trying to figure out how many particles are in 8.1 moles of C₂H₄O. Can someone explain the steps to calculate this?
D danisjohn Member Aug 26, 2025 #2 To find the number of particles in 8.1 mol of C₂H₄O, multiply by Avogadro’s number (6.022 × 10²³ particles/mol). 8.1 mol × 6.022 × 10²³ = 4.87782 × 10²⁴ particles. So, 8.1 mol of C₂H₄O contains approximately 4.88 × 10²⁴ particles.
To find the number of particles in 8.1 mol of C₂H₄O, multiply by Avogadro’s number (6.022 × 10²³ particles/mol). 8.1 mol × 6.022 × 10²³ = 4.87782 × 10²⁴ particles. So, 8.1 mol of C₂H₄O contains approximately 4.88 × 10²⁴ particles.
R Robert Willian Member Aug 26, 2025 #3 8.1 mol of C₂H₄O contains approximately 4.88 × 10²⁴ particles.
R rathore Member Aug 26, 2025 #4 4.88 × 10²⁴ particles (molecules) of C₂H₄O. Calculation: N=n×NA=8.1 mol×6.022×1023 mol−1=4.87782×1024N = n \times N_A = 8.1\ \text{mol} \times 6.022\times10^{23}\ \text{mol}^{-1} = 4.87782\times10^{24}N=n×NA=8.1 mol×6.022×1023 mol−1=4.87782×1024 ≈ 4.88 × 10²⁴.
4.88 × 10²⁴ particles (molecules) of C₂H₄O. Calculation: N=n×NA=8.1 mol×6.022×1023 mol−1=4.87782×1024N = n \times N_A = 8.1\ \text{mol} \times 6.022\times10^{23}\ \text{mol}^{-1} = 4.87782\times10^{24}N=n×NA=8.1 mol×6.022×1023 mol−1=4.87782×1024 ≈ 4.88 × 10²⁴.
S simran Member Aug 26, 2025 #5 Particles=8.1 mol×6.022×1023 particles/mol=4.88×1024 particles= 4.88 \times 10^{24} \text{ particles}=4.88×1024 particles
Particles=8.1 mol×6.022×1023 particles/mol=4.88×1024 particles= 4.88 \times 10^{24} \text{ particles}=4.88×1024 particles
